Question

Answer 1

\(N=\dfrac{2L}{3,4}=\dfrac{2.2550}{3,4}=1500\left(Nu\right)\\ a,H=2A+3G\\ Mà.theo.đề.bài:\\ \dfrac{3G}{2A}=3,5\\ \Leftrightarrow3G=7A\\ \Leftrightarrow\dfrac{G}{A}=\dfrac{7}{3}\\ Mà:G+A=\dfrac{N}{2}=750\left(Nu\right)\\ Vậy:A=T=225\left(Nu\right);G=X=525\left(Nu\right)\\ b,Mạch.1:A_1=105\left(Nu\right);T_1=A-A_1=225-105=120\left(Nu\right)\\ G_1=225\left(Nu\right);X_1=G-G_1=525-225=300\left(Nu\right)\\ Mạch.2:A_2=T_1=120\left(Nu\right);T_2=A_1=105\left(Nu\right)\\ X_2=G_1=225\left(Nu\right);G_2=X_1=300\left(Nu\right)\)

Answer 2

thank you