Thay x=5 vào PT, ta được:
\(\dfrac{m}{3}=\dfrac{5-2}{5-4}+\dfrac{5-3}{5-2}=3+\dfrac{2}{3}=\dfrac{11}{3}\)
=>m=11
=>\(\dfrac{x-2}{x-4}+\dfrac{x-3}{x-2}=\dfrac{11}{3}\)
=>\(\dfrac{x^2-4x+4+x^2-7x+12}{\left(x-2\right)\left(x-4\right)}=\dfrac{11}{3}\)
=>11(x^2-6x+8)=3(2x^2-11x+16)
=>11x^2-66x+88-6x^2+33x-48=0
=>5x^2-33x+40=0
=>x=5 hoặc x=8/5