\(a,\left(3x-1\right)\left(x+3\right)=\left(2-x\right)\left(5-3x\right)\\ \Rightarrow3x^2-x+9x-3=10-5x-6x+3x^2\\ \Rightarrow8x-3=10-11x\\ \Rightarrow8x+11x=10+3\\ \Rightarrow19x=13\\ \Rightarrow x=\dfrac{13}{19}\\ ------------\\ b,\left(x+5\right)\left(2x-1\right)=\left(2x+3\right)\left(x+1\right)\\ \Rightarrow2x^2+10x-x-5=2x^2+3x+2x+3\\ \Rightarrow9x-5=5x+3\\ \Rightarrow9x-5x=3+5\\ \Rightarrow4x=8\\ \Rightarrow x=8:4\\ \Rightarrow x=2\)
\(---------\\ c,\left(x+1\right)\left(x+9\right)=\left(x+3\right)\left(x+5\right)\\ \Rightarrow x^2+x+9x+9=x^2+3x+5x+15\\ \Rightarrow10x+9=8x+15\\ \Rightarrow10x-8x=15-9\\ \Rightarrow2x=6\\ \Rightarrow x=3\)
\(-----------\\ d,\left(3x+5\right)\left(2x+1\right)=\left(6x-2\right)\left(x-3\right)\\ \Rightarrow6x^2+10x+3x+5=6x^2-2x-18x+6\\ \Rightarrow13x+5=-20x+6\\ \Rightarrow13x+20x=6-5\\ \Rightarrow33x=1\\ \Rightarrow x=\dfrac{1}{33}\)
a: =>(3x-1)(x+3)=(3x-5)(x-2)
=>3x^2+9x-x-3=3x^2-6x-5x+10
=>8x-3=-11x+10
=>19x=13
=>x=13/19
b: \(\Leftrightarrow2x^2-x+10x-5=2x^2+2x-3x-3\)
=>9x-5=-x-3
=>10x=2
=>x=1/5
c: \(\Leftrightarrow x^2+10x+9=x^2+8x+15\)
=>2x=6
=>x=3
d: \(\Leftrightarrow6x^2+3x+10x+5=6x^2-18x-2x+6\)
=>13x+5=-20x+6
=>33x=1
=>x=1/33
e: =>x^2+4x+4+2x-8=x^2-6x+8
=>6x-4=-6x+8
=>12x=12
=>x=1
f: =>2x^2-3x+2x-3-3x+6=2x^2-4x+2
=>-4x+3=-4x+2
=>3=2(loại)
