\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}\\ =>\dfrac{x}{2}=\dfrac{2y}{6}=\dfrac{3z}{15}\)
áp dụng dãy tỉ s bằng nhau ta có
\(\dfrac{x}{2}=\dfrac{2y}{6}=\dfrac{3z}{15}=\dfrac{x-2y+3z}{2-6+15}=\dfrac{33}{11}=3\)
\(=>x=3=6\\ y=3\cdot3=9\\ z=3\cdot5=15\)
`x/2 = y/3 = z/5`
`->x/2 =` \(\dfrac{2y}{6}=\dfrac{3z}{15}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{2}=\dfrac{2y}{6}=\dfrac{3z}{15}=\dfrac{x-2y+3z}{2-6+15}=\dfrac{33}{11}=3\)
`-> x/2 = 3 | y/3 = 3 | z/5 = 3`
`-> x=6, y=9, z=15`