Question

Answer 1

\(\dfrac{2x-4y}{x^2-4y^2}=\dfrac{2\left(x-2y\right)}{x^2-\left(2y\right)^2}=\dfrac{2\left(x-2y\right)}{\left(x-2y\right)\left(x+2y\right)}=\dfrac{2}{x+2y}\)

Answer 2

`(2x-4y)/(x^2-4y^2)`

`= (2(x-2y))/((x-2y)(x+2y))`

`=2/(x+2y)`