a: \(=\dfrac{x^3+2x^2+2\left(x-5\right)\left(x+5\right)-5x+50}{2x\left(x+5\right)}\)
\(=\dfrac{x^3+2x^2-5x+50+2x^2-50}{2x\left(x+5\right)}\)
\(=\dfrac{x^3+4x^2-5x}{2x\left(x+5\right)}=\dfrac{x\left(x+5\right)\left(x-1\right)}{2x\left(x+5\right)}=\dfrac{x-1}{2}\)
b: Để A=1 thì x-1=2
=>x=3
Để A=-3 thì x-1=-6
=>x=-5(loại)