Question

Answer 1

a: \(\dfrac{x^2-3x+2}{x^2-1}=\dfrac{\left(x-1\right)\left(x-2\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{x-2}{x+1}\)

b: \(\dfrac{4x^3-x}{5-10x}=\dfrac{x\left(4x^2-1\right)}{5\left(1-2x\right)}=\dfrac{-x\left(1-2x\right)\left(1+2x\right)}{5\left(1-2x\right)}=-\dfrac{2x^2+x}{5}\)