Question

Answer 1

\(A=\dfrac{x-\sqrt{x}}{1-\sqrt{x}}+\dfrac{x-1}{\sqrt{x}+1}\\ =\dfrac{-\sqrt{x}\left(\sqrt{x}-1\right)}{\sqrt{x}-1}+\dfrac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{\sqrt{x}+1}\\ =-\sqrt{x}+\left(\sqrt{x}-1\right)\\ =-\sqrt{x}+\sqrt{x}-1\\ =-1\\ \Rightarrow D\)

Answer 2

C. -2¥x