Quy đổi hỗn hợp thành: \(\left\{{}\begin{matrix}Fe:x\left(mol\right)\\O:y\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow56x+16y=13,36\left(1\right)\)
\(n_{NO}=\dfrac{1,344}{22,4}=0,06\left(mol\right)\)
Quá trình oxi hoá - khử:
\(Fe^0-3e\rightarrow Fe^{+3}\\ O^0+2e\rightarrow O^{-2}\\ N^{+5}+3e\rightarrow N^{+2}\)
\(\xrightarrow[]{BTelectron}3n_{Fe}=2n_O+3n_{NO}\)
\(\Rightarrow3x=2y+3.0,06\left(2\right)\\ \left(1\right);\left(2\right)\Rightarrow\left\{{}\begin{matrix}x=0,185\\y=0,1875\end{matrix}\right.\)
\(\xrightarrow[]{BTNT.Fe}n_{Fe\left(NO_3\right)_3}=n_{Fe}=0,185\left(mol\right)\\ \Rightarrow m=0,185.242=44,77\left(g\right)\)
Đúng 3
Bình luận (0)
