`x:0,25+x:0,2-x xx3+x:0,125=7`
`x xx4+x xx5-x xx3+x xx8=7`
`x xx(4+5-3+8)=7`
`x xx14=7`
`x=7:14=1/2`
x : 0,25 + x : 0,2 - x * 3 + x : 0,125 = 7
x * 4 + x * 5 - x * 3 + x * 8 = 7
x * (4 + 5 - 3 + 8) = 7
x * 14 = 7
x = 7 : 14
x = 1/2
=> \(x\times\left(4+5-3+8\right)=7\)
\(x=\dfrac{7}{4+5-3+8}=\dfrac{1}{2}=0,5\)
X x 4 + X x 5 - X x 3 + X x 8 = 7
X x ( 4 + 5 - 3 + 8 ) = 7
X x 14 = 7
X = 7 : 14
X = 0,5