Question

Answer 1

\(\lim\limits_{x\rightarrow-1}\dfrac{x^2+2x+1}{2x^3+2}=\lim\limits_{x\rightarrow-1}\dfrac{\left(x+1\right)^2}{2\left(x+1\right)\left(x^2-x+1\right)}=\lim\limits_{x\rightarrow-1}\dfrac{x+1}{2\left(x^2-x+1\right)}=\dfrac{0}{6}=0\)