a: \(=\dfrac{-1}{3}\cdot\dfrac{6}{13}\cdot\dfrac{9}{10}\cdot\dfrac{13}{36}=\dfrac{-1}{3}\cdot\dfrac{6}{10}\cdot\dfrac{1}{4}=\dfrac{-2}{5\cdot4}=\dfrac{-2}{20}=\dfrac{-1}{10}\)
b: \(=\dfrac{10}{117}+\dfrac{27}{143}+\dfrac{11}{13}=\dfrac{10+99}{117}+\dfrac{27}{143}=\dfrac{1442}{1287}\)
c: \(=\dfrac{-5}{7}\left(\dfrac{3}{11}+\dfrac{8}{11}\right)+\dfrac{9}{7}=\dfrac{-5}{7}+\dfrac{9}{7}=\dfrac{4}{7}\)
d: \(=\dfrac{5}{9}\cdot\left(-18\right)=-10\)
Đúng 1
Bình luận (0)
