\(x^2+2y^2-3xy-2x+4y=0\)
\(\Leftrightarrow\left(x-y\right)\left(x-2y\right)-2\left(x-2y\right)=0\)
\(\Leftrightarrow\left(x-2y\right)\left(x-y-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2y\\x=y+2\end{matrix}\right.\)
Thế xuống pt dưới:
\(\Rightarrow\left[{}\begin{matrix}\left(4y^2-5\right)^2=2y+5\\\left(\left(y+2\right)^2-5\right)^2=9\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(2y^2+y-2\right)\left(4y^2-2y-5\right)=0\\\left(y^2+4y-4\right)\left(y^2+4y+2\right)=0\end{matrix}\right.\)
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