Question

Answer 1

\(=2\left(x^2+2x-15\right)=2\left(x+5\right)\left(x-3\right)\)

Answer 2

\(2x^2+4x-30\\ =2\left(x^2+2x-15\right)\\ =2\left[\left(x^2+5x\right)-\left(3x+15\right)\right]\\ =2\left[x\left(x+5\right)-3\left(x+5\right)\right]\\ =2\left(x-3\right)\left(x+5\right)\)