Question

Answer 1

Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{2}=\dfrac{y-x}{7-5}=\dfrac{48}{2}=24\)

\(\dfrac{x}{5}=24\Rightarrow x=120\\ \dfrac{y}{7}=24\Rightarrow y=168\\ \dfrac{z}{2}=24\Rightarrow z=48\)

Answer 2

Áp dụng t/c dtsbn ta có:

x5=24⇒x=120y7=24⇒y=168z2=24⇒z=48

Answer 3

\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{2}\text{ và }y-x=48\)

\(\text{Áp dụng tính chất dãy tỉ số bằng nhau:}\)

\(\dfrac{x}{5}=\dfrac{y}{7}=\dfrac{z}{2}=\dfrac{y-x}{7-5}=\dfrac{48}{2}=24\)

\(\Rightarrow x=24.5=120\)

\(y=24.7=168\)

\(x=24.2=48\)