Cơ mà kia là x->-2 à?
\(\lim\limits_{x\rightarrow-2}\dfrac{x^2+7x+10}{\sqrt{x+3}-1}=\lim\limits_{x\rightarrow-2}\dfrac{\left(x+2\right)\left(x+5\right)\left(\sqrt{x+3}+1\right)}{x+2}=\lim\limits_{x\rightarrow-2}\left(x+5\right)\left(\sqrt{x+3}+1\right)=6\)