a) \(P=\dfrac{1+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}.\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}+1}=\dfrac{\sqrt{x}-1}{\sqrt{x}}\)
b) \(P=\dfrac{\sqrt{x}-1}{\sqrt{x}}=\dfrac{\sqrt{\dfrac{1}{9}}-1}{\sqrt{\dfrac{1}{9}}}=\dfrac{\dfrac{1}{3}-1}{\dfrac{1}{3}}=\dfrac{-\dfrac{2}{3}}{\dfrac{1}{3}}=-2\)