\(VT=3\left(\dfrac{yz}{x}+\dfrac{xz}{y}\right)+4\left(\dfrac{yz}{x}+\dfrac{xy}{z}\right)+5\left(\dfrac{xz}{y}+\dfrac{xy}{z}\right)\)
\(VT\ge3.2\sqrt{\dfrac{xyz^2}{xy}}+4.2\sqrt{\dfrac{xzy^2}{xz}}+5.2\sqrt{\dfrac{yzx^2}{yz}}=6z+8y+10x\) (đpcm)
Dấu "=" xảy ra khi \(x=y=z\)