Question

Answer 1

\(a,=\left(x+3\right)^2=\left(97+3\right)^2=100^2=10000\\ b,=\left(x-3\right)^3=\left(13-3\right)^3=10^3=1000\\ c,=\left(3x+7\right)^2=\left(3+7\right)^2=10^2=100\\ d,=\left(5x-\dfrac{1}{5}y\right)^2=\left[5\cdot\left(-\dfrac{1}{5}\right)-\dfrac{1}{5}\cdot\left(-5\right)\right]^2=\left(-1+1\right)^2=0\)

Answer 2

a)\(=\left(x+3\right)^2\) Thay x=97 vào đc 100²

b)\(=\left(x-3\right)^2\) Thay x=13 vào đc 10²

c)\(=\left(3x+7\right)^2\) Thay x=1 vào đc 10²

d)\(=\left(5x-\dfrac{1}{5}y\right)^2\) Thay \(x=-\dfrac{1}{5};y=-5\) ta đc 0²=0