Question

Answer 1

a: \(\widehat{C}=90^0-60^0=30^0\)

Answer 2

a, \(\widehat{C}=180^0-90^0-60^0=30^0\)

b, \(\widehat{ADH}=180^0-\widehat{B}-\widehat{HAD}=180^0-60^0-\dfrac{1}{2}\widehat{BAC}=120^0-45^0=75^0\)

c, \(\widehat{HAD}=90^0-\widehat{ADH}=15^0\)