b) Có \(\dfrac{5}{2}\sqrt{\dfrac{1}{6}}=\sqrt{\left(\dfrac{5}{2}\right)^2.\dfrac{1}{6}}=\sqrt{\dfrac{25}{24}}\)
\(6\sqrt{\dfrac{1}{37}}=\sqrt{\dfrac{6^2}{37}}=\sqrt{\dfrac{36}{37}}\)
Có \(\dfrac{25}{24}>1>\dfrac{36}{37}\)
\(\Rightarrow\dfrac{5}{2}\sqrt{\dfrac{1}{6}}>6\sqrt{\dfrac{1}{37}}\)