E1. Give the correct form of the verb in brackets.

1. Look! The car (go) is going so fast.

2. Listen! Someone (cry) is crying in the next room.

3Is your brother (walk) walking with a dog over there at present?

4. they (try) are trying to pass the examination.

5. It’s 7 o’clock, and my parents (cook)are cooking dinner in the kitchen.

6. Be quiet! You (talk)are talking so loudly.

7. I (not stay) am not staying at home at the moment.

8. Now she (lie) is lying to her mother about her bad marks.

9. At the present, they (travel)are traveling to Washington.

10. He (not work) is not working in the construction site now.

E2. MIX ( HOMEWORK 1)

1. What do you (do)do on Sundays?

2. He usually jogs (jog) in the morning.

3. My brother is watching (watch) TV at the moment.

4. Hoa (not go) doesn't go fishing in the winter.

5. Her sister is skipping (skip) now.

6. There isn't(not be) any water in the bottle.

7. I can speak(speak) English.

8. She is visiting (visit) her aunt now.

9. At the moment, the children (play) are playing  soccer in the garden.

10. She is going(go) camping tomorrow.

11. My sister always (wear)wears  nice clothes for work. Today she (wear) wears a blue jacket and shirt.

12. Look! Why are you (buy) buying so much food?

     - Because we (have)are having a party tonight.

E3: ( HOMEWORK 2)

1- Where (be) is your mother? – She (sleep) is sleeping in her room.

2- It ( get) is getting warmer and warmer.

3- Hoa always (get)gets up early to do morning exercise.

4- Hoa is always (forget) forgetting her homework.

5- My brother is always ( go)going to school late.

6- Hoa ( get) is getting more and more intelligent.

7- Listen! Someone ( knock) is knocking at the door.

8- Don’t talk in our class! Our teacher(teach) is teaching the lesson.

9. Look! Why  are you (buy)buying so much food?

    - Because we (have)are having a party tonight.

10. It (not rain)isn't raining right now. The sun (shine)is shining and the sky is blue.

11. Alice (not take)doesn't take the bus to school every day. She usually (walk)walks instead.

12. At the moment, Hung ( play)is playing football with his brother.

#\(Vion.Serity\)

#\(yGLinh\)

\(e,3-\left(\dfrac{1}{6}-x\right).\dfrac{2}{3}=\dfrac{2}{3}\)

 \(\left(\dfrac{1}{6}-x\right).\dfrac{2}{3}=3-\dfrac{2}{3}\)

\(\left(\dfrac{1}{6}-x\right).\dfrac{2}{3}=\dfrac{9}{3}-\dfrac{2}{3}\)

\(\left(\dfrac{1}{6}-x\right).\dfrac{2}{3}=\dfrac{7}{3}\)

\(\dfrac{1}{6}-x=\dfrac{7}{3}:\dfrac{2}{3}\)

\(\dfrac{1}{6}-x=\dfrac{7}{3}.\dfrac{3}{2}\)

\(\dfrac{1}{6}-x=\dfrac{7}{2}\)

\(x=\dfrac{1}{6}-\dfrac{7}{2}\)

\(x=\dfrac{1}{6}+\dfrac{-21}{6}\)

\(x=\dfrac{-20}{6}\)

\(f,8x-4x=1208\)

\(\left(8-4\right).x=1208\)

  4       . x =1208

 x=1208 : 4

 x= 302

g,0,3. x +0,6.x=9

  (0,3+0,6).x=9

    0,9 .x=9

          x =9:0,9

          x= 10 

\(h,\dfrac{1}{2}x+\dfrac{2}{5}x=\dfrac{-18}{25}\)

 \(\left(\dfrac{1}{2}+\dfrac{2}{5}\right).x=\dfrac{-18}{25}\)

\(\left(\dfrac{5}{10}+\dfrac{4}{10}\right)x=\dfrac{-18}{25}\)

\(\dfrac{9}{10}x=\dfrac{-18}{25}\)

\(x=\dfrac{-18}{25}:\dfrac{9}{10}\)

\(x=\dfrac{-18}{25}.\dfrac{10}{9}\)

x= \(\dfrac{-4}{5}\)

e ] 3 - [ \(\dfrac{1}{6}\) - x ] . \(\dfrac{2}{3}\)  = \(\dfrac{2}{3}\)  

     3 - [ \(\dfrac{1}{6}\) - x ] = \(\dfrac{2}{3}\) : \(\dfrac{2}{3}\)

     3 - [ \(\dfrac{1}{6}\) - x ] = 1

          [ \(\dfrac{1}{6}\) - x ] = 3 - 1

            \(\dfrac{1}{6}\) - x = 2

                  x = \(\dfrac{1}{6}\) - 2

                  x = \(\dfrac{-11}{6}\)

f ] 8x - 4x = 1208

    [ 8 - 4 ]x = 1208

             4x = 1208

               x = 1208 : 4

               x = 302

g ] 0,3x + 0,6x = 9

    [ 0,3 + 0,6 ]x = 9

                 0,9x = 9

                      x = 9 : 0,9

                      x = 10

h ] \(\dfrac{1}{2}\)x + \(\dfrac{2}{5}\)x = \(\dfrac{-18}{25}\)

    [ \(\dfrac{1}{2}\) + \(\dfrac{2}{5}\) ]x = \(\dfrac{-18}{25}\)

              \(\dfrac{9}{10}\)x = \(\dfrac{-18}{25}\) 

                   x = \(\dfrac{-18}{25}\)  : \(\dfrac{9}{10}\)

                   x = \(\dfrac{-4}{5}\)

\(\sqrt{4x+12}-3\sqrt{x+3}+\dfrac{4}{3}\sqrt{9x+27}=6\left(dk:x\ge-3\right)\)

\(\Leftrightarrow\sqrt{4\left(x+3\right)}-3\sqrt{x+3}+\dfrac{4}{3}\sqrt{9\left(x+3\right)}=6\\ \Leftrightarrow2\sqrt{x+3}-3\sqrt{x+3}+4\sqrt{x+3}=6\)

Đặt \(\sqrt{x+3}=a\left(dk:a\ge-3\right)\)

Pt trở thành : \(2a-3a+4a=6\Leftrightarrow a\left(2-3+4\right)=6\Leftrightarrow3a=6\Leftrightarrow a=2\left(tm\right)\)

Ta có : \(\sqrt{x+3}=2\Leftrightarrow\left(\sqrt{x+3}\right)^2=2^2\Leftrightarrow x+3=4\Leftrightarrow x=1\left(tmdk\right)\)

(Ở đây không cần xét giá trị tuyệt đối vì có dk ban đầu rồi nha.)

Vậy \(S=\left\{1\right\}\)

\(=2^{12}\cdot2^3\cdot2^9=2^{24}\)

Chọn A. "Tất cả người dân Việt Nam đều không được tiêm Vacxin ngừa Covid"

=> 

Mệnh đề ban đầu cho biết rằng :  "Tất cả người dân Việt Nam đều được tiêm Vacxin ngừa Covid". Để tạo thành một mệnh đề phủ định,chúng ta cần phủ định cả phần "được tiêm Vacxin ngừa Covid"

+ Phủ định "Tất cả người dân Việt Nam đều không được tiêm Vacxin ngừa Covid" mang ý nghĩa là không có ai trong số người dân Việt Nam được tiêm Vacxin ngừa Covid. Điều này đúng với yêu cầu của câu hỏi, nên đáp án A là mệnh đề phủ định phù hợp.

P/s: Nếu cậu hong hỉu có thể tham khảo đây nhen : https://hoidap247.com/cau-hoi/6038613 :>

x⁷.x⁴.x³ = x⁷⁺⁴⁺³ = x¹⁴

\(x^7+x^4+x^3=x^{7+4+3}=x^{14}\)

a. Ta có: ( x-2)² \(\ge\) 0 , \(\forall\) x

=> ( x-2)² +2023 \(\ge\) 2023

Vậy ...

Dấu bằng xảy ra khi x-2 = 0

b. (x-3)²+(y-2)²-2018

Ta có: \((x-3)^2 \ge0,\forall x\)

           \((y-2) ^2 \ge0,\forall y\) 

=> ( x-3)² + ( y-2)² \(\ge\) 0

=>  ( x-3)² + ( y-2)²-2018 \(\ge\) -2018, \(\forall\) x,y 

Vậy ...

Dấu bằng xảy ra khi x-3=0

                                 y-2=0

c. ( x+1)² +100

Ta có : ( x+1)² \(\ge0,\forall x\) 

=> ( x+1)²+100 \(\ge\) 100

Vậy ...

Dấu bằng xảy ra khi x+1=0

2:

a: -2/3*x=4/15

=>x=-4/15:2/3=-4/15*3/2=-12/30=-2/5

b: 21/13x=-7/26

=>x=-7/26:21/13=-7/26*13/21=-1/6

c: -14/25x=-42/35

=>14/25*x=42/35

=>x=42/35:14/25=15/7

d: 22/15x=-8/27

=>x=-8/27:22/15=-8/27*15/22=-20/99

a: \(P=\dfrac{4\sqrt{a}-2+3\sqrt{a}-6-5\sqrt{a}+7}{\left(\sqrt{a}-2\right)\left(2\sqrt{a}-1\right)}\cdot\dfrac{5\sqrt{a}\left(\sqrt{a}-2\right)}{2\sqrt{a}+3}\)

\(=\dfrac{2\sqrt{a}-1}{\left(2\sqrt{a}-1\right)}\cdot\dfrac{5\sqrt{a}}{2\sqrt{a}+3}=\dfrac{5\sqrt{a}}{2\sqrt{a}+3}\)

b: \(\sqrt{a}=\sqrt{2}+1-\sqrt{2}+1=2\)

=>a=4

Khi a=4 thì \(P=\dfrac{5\cdot2}{2\cdot2+3}=\dfrac{10}{7}\)

c: P nguyên

=>5căn a chia hết cho 2căn a+3

=>10căn a chia hết cho 2căn a+3

=>10căn a+15-15 chia hết cho 2căn a+3

=>\(2\sqrt{a}+3\in\left\{3;5;15\right\}\)

=>\(a\in\left\{1;36\right\}\)

1 The children always play games noisily.

2 We hope the project will be successful.

3 He looked at me sadly.

4 Snails move slowly.